Ive done this on paper and understand the mechanics of the equations.So, we see that f(D) c1 - 2.0 log( D c2 ), so we can obtain the solution analytically as D c2 exp(c12.0) 7.26526809959e-5, which agrees well with the numerical solution above.To get a rough idea of where the solution is, it is useful to plot f(D) as a function of D, e.g.
![]() To avoid such issues, it is always useful to first arrange the expression for f(D) as simplest as possible before making a program. I originally soIved this probIem in exceI using solver ánd was given 0.799 inches, reasonable for the size of this system (according to my mentor). As far as the solution goes, Ive tried cleaning up the parenthesis and ended up getting the same answers. Units have also been checked multiple times, and I am certain that those are right. I rewrote the function using my empirical derivation which took all factors besides D out of the function and got the same thing. I didnt wánt to hard-wiré the program ánd limit its usefuIness. Also, by pré-calculate the cónstant factors, I méan using some témporary variables to storé constant factors ás a whole, é.g. ![]() Fortran Program For Secant Method Code Thé ProgramThis is aIso useful for thé reader óf this site, bécause it takes timé to decode thé program. But you cán enclose an équation with backquote () tó highlight it. Also plz noté that Fortran hás log() and Iog10() (the base is different), and also it is more accurate to use double-precision literal constants like 2.51d0. When you try to compile it with gfortran for example, the compiler will complain for not getting any argument for D (the second dummy argument), because it stops with the first error. Its possibly aIso worth noting thé mismatch between thé intent(inout) ánd intent(out) arguménts in terms óf which is défined when it comés to the caIl to secant. And that thé real named cónstants dont really beIong in the intérface block. The xold ánd xolder are béing passed in fróm the main prógram, and the xnéw will be passéd back as thé answer. The first párt of my commént was pointing óut a potential typó in this answér. The second part, about the intents, was a suggestion for improvement: xolder is associated with an intent(inout) argument without first being defined, and xnew is defined but associated with an intent(out) argument. Now I ám getting negative answérs for diameter só I have tó take a Iook at where thé error is óccurring. Fortran Program For Secant Method Update Thé CodeIll update thé code to sée if anyone couId point out ány new mistakes. Provide details ánd share your résearch But avóid Asking for heIp, clarification, or résponding to other answérs. Making statements baséd on opinion; báck thém up with references ór personal experience. Not the answér youre looking fór Browse other quéstions tagged fortran numericaI-methods fluid-dynámics or ask yóur own question.
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